Answer :-
- Area of Rectangle is 57.12 cm² .
Explanation :-
As per the provided information in the given question, we have been given that the Length of Rectangle is 11.2 cm . Its Breadth is given as 5.1 cm . And, we have been asked to calculate the Area of Rectangle .
For calculating the Area , we will use the Formula :-
[tex] \bigstar \: \: \: \boxed {\sf { \: Area \: of \: Rectangle \: = \: Lenght \: \times \: Breadth \: }} [/tex]
Therefore , by Substituting the given values in the above Formula :-
[tex] \dag \: \: \: \sf {Area \: of \: Rectangle \: = \: Lenght \: \times \: Breadth} [/tex]
[tex] \longmapsto \: \: \: \sf {Area \: of \: Rectangle \: = \: 11.2 \: \times \: 5.1} [/tex]
[tex] \longmapsto \: \: \: \textbf {\textsf {Area \: of \: Rectangle \: = \: 57.12 }} [/tex]
Hence :-
- Area of Rectangle = 57.12 cm² .
[tex] \underline {\rule {205pt} {4pt}} [/tex]
Additional Information :-
[tex] \begin{gathered} \begin{gathered} \begin{gathered}\begin{gathered}\boxed{\begin{array}{c} \\ \underline{ { \textbf {\textsf \red{ \dag \: \: More \: Formulas \: \: \dag}}}} \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Square} = Side \times Side} \\ \\ \\ \footnotesize\bigstar \: \bf{Area \: _{Rectangle} = Lenght \times Breadth} \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Triangle} = \frac{1}{2} \times Base \times Height } \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Parallelogram} = Base \times Height} \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Trapezium} = \frac{1}{2} \times [ \: A + B \: ] \times Height } \\ \\ \\ \footnotesize \bigstar \: \bf {Area \: _{Rhombus} = \frac{1}{2} \times Diagonal \: 1 \times Diagonal \: 2}\end{array}}\end{gathered}\end{gathered} \end{gathered} \end{gathered} [/tex]
[tex] \underline {\rule {205pt} {4pt}} [/tex]
Note :-
- Kindly Scroll the Screen from Right to Left for Better View .
