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Sagot :
The sequence an = 1 + (-3/7)^n is neither an arithmetic progression nor a geometric progression
The first ten terms of the sequence are 0.5714, 1.1837, 0.9213, 1.0337, 0.9855, 1.0062, 0.9973, 1.0011, 0.9995 and 1.0002
How to determine the first ten terms?
The nth term of the sequence is given as:
an = 1 + (-3/7)^n
The first ten terms are calculated as follows:
a1 = 1 + (-3/7)^1 = 0.5714
a2 = 1 + (-3/7)^2 = 1.1837
a3 = 1 + (-3/7)^3 = 0.9213
a4 = 1 + (-3/7)^4 = 1.0337
a5 = 1 + (-3/7)^5 = 0.9855
a6 = 1 + (-3/7)^6 = 1.0062
a7 = 1 + (-3/7)^7 = 0.9973
a8 = 1 + (-3/7)^8 = 1.0011
a9 = 1 + (-3/7)^9 = 0.9995
a10 = 1 + (-3/7)^10 = 1.0002
Read more about sequence at:
https://brainly.com/question/6561461
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