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Figure ABCD is a parallelogram.

Parallelogram A B C D is shown. A diagonal is drawn from point A to point C.

Which sequence could be used to prove that AD = BC?

First prove TriangleABC is congruent to TriangleCDA, and then state AD and BC are corresponding sides of the triangles.
First prove TriangleABC is similar to TriangleCDA, and then state AD and BC are opposite sides of the parallelograms.
First prove ParallelogramABCD is congruent to ParallelogramCDAB, and then state AD and BC are corresponding sides of two parallelograms.
First prove ParallelogramABCD is similar to ParallelogramCDAB, and then state AD and BC are opposite sides of the parallelograms.

Sagot :

tehsilkhan2008

Answer:

A

First prove Triangle ABC is congruent to Triangle CDA, and then state AD and BC are corresponding sides of the triangles.

Hope this helps!

Please Mark Brainleast!!!

The sequence to prove that AD = BC is; First prove ABC is similar to CDA, and then state AD and BC are opposite sides of the parallelograms.

How to prove Quadrilateral Theorems?

From the question, we see that the parallelogram ABCD has a diagonal AC. Thus; AB║ CD and AD║BC.

Now, the parallelogram is divided into two triangles ΔABC and ΔADC by its diagonal AC.

Thus;

∠ACB = ∠DAC  and ∠CAB = ∠ACD  because they are alternate interior angles.

Also, AC = AC  (Reflexive property)

Thus; by ASA congruence postulate, we can say that; ΔABC ≅  ΔADC

Also, by corresponding sides of the congruent triangles are congruent we can say that AD = BC.

Read more baout Quadrilateral proofs at; https://brainly.com/question/2698923

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