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While playing basketball in PE class, Logan lost his balance after making a lay-up and colliding with another student standing behind the basket. His 74-kg body decelerated from 7.6 m/s to 0 m/s, causing the 81-kg student to accelerate from 0 m/s. What is the final velocity of the other student?
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Sagot :

onyebuchinnaji

The final velocity of the other student after the elastic collision with Logan is 6.94 m/s.

Conservation of linear momentum

The final velocity of the other student will be determined by applying the principle of conservation of linear momentum for elastic collision.

  • let u represent  initial velocity
  • let v represent final velocity

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

Substitute the given parameters and solve for final velocity of the other stsudent.

74(7.6) + 81(0) = 74(0) + 81(v₂)

562.4 = 81v₂

v₂ = 562.4/81

v₂ = 6.94 m/s

Thus, the final velocity of the other student after the elastic collision with Logan is 6.94 m/s.

Learn more about conservation of linear momentum here: https://brainly.com/question/7538238

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