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Sagot :

Starrysoul100

[tex]\bold{\huge{\underline{ Solution }}}[/tex]

Given :-

  • We have given one rectangle whose 3 by 4th part is shaded and remaining part is non shaded.

To Find :-

  • We have to find the area of shaded region of the given figure .

Let's Begin :-

Here, We have

  • The dimensions of large rectangle as 12 units and 8 units
  • That is,
  • [tex]\sf{ Length = 9 + 3 = 12 \: units}[/tex]
  • [tex]\sf{ Breath = 4 + 4 = 8 \: units}[/tex]
  • The dimensions of non shaded rectangles are 9 units and 4 units

We know that,

Area of rectangle

[tex]\bold{\red{ = Length {\times} Breath }}[/tex]

Subsitute the required values,

Area of large rectangle

[tex]\sf{ = 12 {\times} 8 }[/tex]

[tex]\sf{ = 96 \:units^{2}}[/tex]

Thus, The area of large rectangle is 96 units² .

Now,

Area of non - shaded rectangle

[tex]\sf{ = 9 {\times} 4 }[/tex]

[tex]\sf{ = 36\: units^{2}}[/tex]

Thus, The area of non shaded rectangle is 36 units² .

Therefore,

Area of shaded region

= Area of large rectangle - Area of non shaded rectangle

Subsitute the required values,

[tex]\sf{ = 96 - 36}[/tex]

[tex]\sf{ = 60\: units^{2}}[/tex]

Hence, The total area of shaded region is 60 sq.units.

BrainlySamrat

✰Given:-

➾Length(L) of bigger rectangle = [tex]\sf{9+3\: =\:12}[/tex]units.

➾Length(l) of smaller rectangle = 9units.

➾Breadth (B) of bigger rectangle = [tex]\sf{4+4 \:=\: 8}[/tex]units.

➾Breadth(b) of smaller rectangle = 4 units.

✰To Find:-

➾Area of the shaded region.

✰Solution:-

➾We can find the area of shaded region by subtracting area of smaller rectangle from area of bigger rectangle(that is whole rectangle including shaded and non shaded region).

So,

➾Area of bigger rectangle = [tex]\sf{L×B}[/tex](putting the value of L and B from the above given)

= [tex]\sf{8×12}[/tex]

= [tex]\sf{96unit^2}[/tex]

Similarly,

➾Area of smaller rectangle = [tex]\sf{l×b}[/tex](putting the value of l and b from the above given)

= [tex]\sf{9×4}[/tex]

= [tex]\sf{36unit^2}[/tex]

Now,

➾Area of shaded region = Area of bigger rectangle - Area of smaller rectangle.

[tex]\sf{= 96-36}[/tex]

[tex]\sf{= 60unit^2.}[/tex]

Therefore, area of shaded region[tex]\sf{= 60unit^2.}[/tex]

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