[tex]\bold{\huge{\underline{ Solution }}}[/tex]
Given :-
- We have given one rectangle whose 3 by 4th part is shaded and remaining part is non shaded.
To Find :-
- We have to find the area of shaded region of the given figure .
Let's Begin :-
Here, We have
- The dimensions of large rectangle as 12 units and 8 units
- That is,
- [tex]\sf{ Length = 9 + 3 = 12 \: units}[/tex]
- [tex]\sf{ Breath = 4 + 4 = 8 \: units}[/tex]
- The dimensions of non shaded rectangles are 9 units and 4 units
We know that,
Area of rectangle
[tex]\bold{\red{ = Length {\times} Breath }}[/tex]
Subsitute the required values,
Area of large rectangle
[tex]\sf{ = 12 {\times} 8 }[/tex]
[tex]\sf{ = 96 \:units^{2}}[/tex]
Thus, The area of large rectangle is 96 units² .
Now,
Area of non - shaded rectangle
[tex]\sf{ = 9 {\times} 4 }[/tex]
[tex]\sf{ = 36\: units^{2}}[/tex]
Thus, The area of non shaded rectangle is 36 units² .
Therefore,
Area of shaded region
= Area of large rectangle - Area of non shaded rectangle
Subsitute the required values,
[tex]\sf{ = 96 - 36}[/tex]
[tex]\sf{ = 60\: units^{2}}[/tex]
Hence, The total area of shaded region is 60 sq.units.