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Find the t-value such that the area in the right tail is 0.005 with 28
degrees of freedom.

Sagot :

agravanteandrei

Answer:

t=3.673900

Explanation:

Given

df = 28df=28 -- degree of freedom

Area = 0.005Area=0.005

Required

Determine the t-value

The given parameters can be illustrated as follows:

P(T > t) = \alphaP(T>t)=α

Where

\alpha = 0.005α=0.005

So, we have:

P(T > t) = 0.005P(T>t)=0.005

To solve further, we make use of the attached the student's t distribution table.

From the attached table,

The t-value is given at the row with df = 28 and \alpha = 0.005α=0.005 is 3.673900

Hence, t = 3.673900t=3.673900

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