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Sagot :
The probability that a worker chosen at random works at least 8 hours is Option C: 0.84 approx.
How to evaluate the probability of a random variable getting at least some fixed value?
Suppose the random variable in consideration be X, and it is discrete.
Then, the probability of X attaining at least 'a' is written as:
[tex]P(X \geq a)[/tex]
It is evaluated as:
[tex]P(X \geq a) = \sum_{\forall \: x_i \geq a} P(X = x_i)[/tex]
The probability distribution of X is:
x f(x) = P(X = x)
6 0.02
7 0.11
8 0.61
9 0.15
10 0.09
Worker working at least 8 hours means X attaining at least 8 as its values.
Thus, probability of a worker chosen at random working 8 hours is
P(X ≥ 8) = P(X = 8) + P(X = 9) +P(X = 10) = 0.85 ≈ 0.84 approx.
By the way, this probability distribution seems incorrect because sum of probabilities doesn't equal to 1.
The probability that a worker chosen at random works at least 8 hours is Option C: 0.84 approx.
Learn more about probability distributions here:
https://brainly.com/question/14882721
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