Welcome to Westonci.ca, the ultimate question and answer platform. Get expert answers to your questions quickly and accurately. Explore thousands of questions and answers from a knowledgeable community of experts on our user-friendly platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

A chemistry teacher adds 50. 0 mL of 1. 50 M H2SO4 solution to 200 mL of water. What is the concentration of the final solution? Use M subscript i V subscript i equals M subscript f V subscript f. 0. 300 M 0. 375 M 6. 00 M 7. 50 M.

Sagot :

The concentration of the final solution after mixing water into the H₂SO₄ is 0.375 M.

How do we calculate the concentration?

Concentration in terms of molarity will be calculated by using the below formula as:

M₁V₁ = M₂V₂, where

M₁ = molarity of H₂SO₄ = 1.50 M

V₁ = volume of H₂SO₄ = 50 mL

M₂ = molarity of water = ?

V₂ = volume of water = 200 mL

On putting all values on the above equation, we get

M₂ = (1.50)(50) / (200) = 0.375 M

Hence option (2) is correct.

To know more about molarity, visit the below link:

https://brainly.com/question/14469428