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Sagot :
The Critical z-values are -1.96 and 1.96 option second is correct.
It is given that the teachers were allowed to choose supplementary curriculum for their classes versus teachers who were assigned all curricular resources for use in their classes.
It is required to find the critical z-values.
What is the critical value of Z?
It is defined as the area region enclosed by the standard normal curve or bell curve. It gives an idea about every variable, and what value of probability the variables acquire.
We are assuming the data given below:
x = 3.5
[tex]\mu =3.3[/tex]
[tex]\sigma = 0.6[/tex]
n = 40
We know the formula for the Z score:
[tex]\rm Z = \frac{x-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex]
[tex]\rm Z = \frac{3.5-3.3}{\frac{0.6}{\sqrt{40} } }[/tex]
Z = 2.10
The area under the normal distribution curve:
P(Z= 2.10) = 0.9821 ( from the z table)
We have null hypothesis H0: in the two groups, the level of job satisfaction is the same ie. with no difference.
H1: There is a significant difference in levels of job satisfaction.
The above hypothesis defined that the test is two-tailed which means there will be two rejection regions.
The critical z-values are:
-1.96 and 1.96 (from the critical value calculator at a 5% significance level with two-tailed)
Thus, the Critical z-values are -1.96 and 1.96 option second is correct.
Learn more about the critical value here:
https://brainly.com/question/13686040
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