The wavelength of the sound wave if the frequency is increased to the given value is 0.44m.
Wavelength is simply the distance over which the shapes of waves are repeated. It is the spatial period of a periodic wave.
It is expressed as;
[tex]\lambda = \frac{v}{f}[/tex]
Where v is velocity and f is frequency.
Given the data in the question;
Speed of sound wave; [tex]v =\ ?[/tex]
Wavelength of sound wave b; [tex]\lambda _b = ?[/tex]
First, we calculate the velocity of the sound wave in air from sound wave a.
[tex]\lambda = \frac{v}{f}\\ \\1.76m= \frac{v}{196s^{-1}}\\\\v = 1.76m * 196s^{-1}\\\\v = 344.96m/s[/tex]
Now, we determine the wavelength of sound wave b using the velocity of sound wave in air calculated above.
[tex]\lambda = \frac{v}{f}\\ \\\lambda = \frac{344.96m/s}{784s^{-1}}\\\\\lambda = 0.44m[/tex]
Therefore, the wavelength of the sound wave if the frequency is increased to the given value is 0.44m.
Learn more about wavelength: https://brainly.com/question/27120701
Answer:
It decreases by 1.32 meters.
Explanation:
The other person was wrong.
