col8kings
Answered

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A body of mass 5kg is ejected vertically from the ground when a force of 600N acts on it for 0.1s. Calculate the velocity with which the body leaves the ground.​

Sagot :

col7kings

Assuming g=10N

upward force=600N(applied force)

downward force=(W)=(5x10)=50N

net force=600-50

=550N

F=(delta)P/t

(delta)P=m (v-u)

u=0m/s

(delta)P=mv

550=(5)(v)/0.1

550x0.1

55=5v

v=11m/s

col9kings

there was no mention of any gravity acting on the object only applied force ,infact we aren't even given the constant

so many assumptions have been made whyyyyyyy!!!

what's your take on it scientists

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