Answered

Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Join our Q&A platform and get accurate answers to all your questions from professionals across multiple disciplines. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

A bottle is launched from a bottle launcher. The height of the bottle is modeled by the equation h(t) = –16t2 + 78t + 10. How long does it take the bottle to reach the ground?

A.
10 seconds

B.
5 seconds

C.
4.7 seconds

D.
1.1 seconds

Sagot :

Answer:

C: 4.7

Step-by-step explanation:

Axis of symmetry: -b/2a

a=-16

b=78

-78/2(2(-16))= 4.875 seconds in the air.

Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.