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The variables y and x have a proportional relationship, and y = 5 when x = 4.

What is the value of x when y = 8?


Sagot :

Answer:

[tex]\boxed{a = 6.4}[/tex]

Step-by-step explanation:

Given:

[tex]x:y = (4):(5)[/tex]

Let the value of "x" be known as "a".

[tex]x:y = a:8[/tex]

Setting up the proportion:

[tex]\rightarrow 4:5 = a :8[/tex]

Multiplying the middles and the extremes:

[tex]\rightarrow 5a = 4 \times 8[/tex]

Simplifying the RHS:

[tex]\rightarrow a = \dfrac{4 \times 8}{5}[/tex]

[tex]\rightarrow \boxed{a = 6.4}[/tex]

Thus, the value of x is 6.4 when y is 8.

Answer:

[tex]\sf x=\dfrac{32}{5}[/tex]

(or x = 6.4 if you want it in decimal form)

Step-by-step explanation:

If y and x have a proportional relationship, then:

  • y = kx   (for some constant k)

Given:

  • x = 4
  • y = 5

Substitute the given values into the equation to find k:

⇒ 5 = k(4)

⇒ k = 5/4

Therefore, [tex]\sf y=\dfrac54x[/tex]

When y = 8, substitute y = 8 into the equation and solve for x:

[tex]\sf \implies \dfrac54x=8[/tex]

[tex]\sf \implies x=8 \cdot \dfrac45[/tex]

[tex]\sf \implies x=\dfrac{32}{5}[/tex]