Answered

Looking for trustworthy answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Get immediate and reliable solutions to your questions from a community of experienced experts on our Q&A platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

A quantity with an initial value of 200 grows continuously at a rate of 4% per second.
What is the value of the quantity after 1.55 minutes, to the nearest hundredth?

Sagot :

MrRoyal

The growth of the quantity is an illustration of an exponential function

The value of the quantity after 1.55 minutes is 76759.22

How to determine the amount of the quantity?

The given parameters are:

Initial value, a = 2000

Rate, r = 4%

An exponential growth function is represented as:

y = a(1 + r)^x

Substitute the value in the equation

y = 2000(1 + 4%)^x

After 1.55 minuted, x = 1.55 * 60

So, we have:

y = 2000(1 + 4%)^(1.55 * 60)

Evaluate the expression

y = 76759.22

Hence, the value of the quantity after 1.55 minutes is 76759.22

Read more about exponential functions at:

brainly.com/question/24077767

We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.