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Consider a sequence whose first five terms are: 4, 8, 16, 32, 64.
Which function (with domain all integers n 2 1) could be used to define and continue this sequence?
A f(n) = 4(n-1)
® f(n) = 4(2)"-1
f(n) = 4n2
f(n) = 4n

Sagot :

2k2klexa

Answer:

Considere una secuencia cuyos primeros cinco términos son: 4, 8, 16, 32, 64.

¿Qué función (con dominio todos los enteros n 2 1) podría usarse para definir y continuar esta secuencia?

A f(n) = 4(n-1)

® f(n) = 4(2)"-1

f(n) = 4n2

f(n) = 4n

Step-by-step explanation:

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