The value of the hypotenuse y will be equal to y = 2.8 inches.
The volume of the prism is equal to the product of the area of its base and the height of the prism.
[tex]\rm V=Area \ of\ triangular \ base\times Height \ of \ prism[/tex]
The volume oif the prism is =4 cubic inches
Height of the prism = x inches
Base of the right angle isosceles triangle will be =x inches
The hypotenuse is given = y
Now
[tex]\rm V=\dfrac{1}{2}\times Base\times Height \times height \ of \ prism[/tex]
[tex]V=\dfrac{1}{2} \times x \times x \times x[/tex]
[tex]x^3=8[/tex]
[tex]x=2[/tex]
Now by pythagorus theorem
[tex]y^2=h^2+b^2[/tex]
[tex]y^2=x^2+x^2[/tex]
[tex]y^2=2x^2=2\times 2^2[/tex]
[tex]y=2\sqrt{2}=2.82[/tex]
Thus the value of the hypotenuse y will be equal to y = 2.8 inches.
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