Welcome to Westonci.ca, the ultimate question and answer platform. Get expert answers to your questions quickly and accurately. Join our Q&A platform to get precise answers from experts in diverse fields and enhance your understanding. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
Given that the Ferris diameter is 20 meters, with a rate of rotation of 1 turn in 8 minutes, we have;
a. Amplitude: A = 10 meters
Midline: h = 11 meters
Period, P = 8 minutes
b. h(t) = 10•cos((π/4)•t + π) + 11
c. 11 meters
How can the Ferris wheel be evaluated?
The amplitude is the same as the radius of the Ferris wheel,
The radius of the Ferris wheel = 20 ÷ 2 = 10
Therefore;
- Amplitude: A = 10 meters
[tex]the \: midline \: = \frac{max \: height \: + min \: height}{2} [/tex]
Therefore;
[tex]midline \: = \frac{10 + 10 + 1 + 1}{2} = 11[/tex]
- Midline: h = 11 meters
The period is the time to complete one rotation, therefore;
- Period, P = 8 minutes
b. h(t) = A•cos(B•t + C) + h
Where;
B = 2•π/P
When t = 0, h(t) = 1
Which gives;
h(0) = 1 = 10 × cos(B×0 + C) + 11
-10/10 = -1 = cos(C)
C = arcos(-1) = π
Therefore;
- h(t) = 10•cos((π/4)•t + π) + 11
h(0) = 1
h(0) is the minimum value of h(t)
- h(t) cannot be a straight sine function because of the vertical shift
- h(t) cannot be a straight cosine function because at t = 0, is the minimum point
c. After 30 minutes, we have;
h(30) = 10•cos((π/4)×30 + π) + 11 = 11
- The height of a person after 30 minutes is 11 meters
Learn more about the Ferris wheel here:
https://brainly.com/question/86214
Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.