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PLSSS HEELPPP A line passes through (3, -2) and (6, 2).
a. Write an equation for the line in point-slope form.
b. Rewrite the equation in standard form using integers.

a. y+2= 4/3(x+3); -4x+ 3y= -18
b. y+2= 4/3(x-3); -4x+3y= -18
c. y-2= 4/3(x-3); -4x+3y= 18
d. y-3= 4/3(x+2); -4x+3y= 17

Sagot :

semsee45

Answer:

b)

Step-by-step explanation:

Question (a)

[tex]\sf let \ (x_1,y_1)=(3,-2)\\\\\sf let \ (x_2,y_2)=(6,2)[/tex]

[tex]\sf slope \ (m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{2-(-2)}{6-3}=\dfrac43[/tex]

Point-slope formula: [tex]\sf y-y_1=m(x-x_1)[/tex]

Substituting m and point (3, -2) into the formula:

[tex]\sf y-(-2)=\dfrac43(x-3)[/tex]

[tex]\sf y+2=\dfrac43(x-3)[/tex]

Question (b)

Rewrite in standard form:

[tex]\sf y+2=\dfrac43x-4[/tex]

[tex]\sf \implies y=\dfrac43x-6[/tex]

[tex]\sf \implies 3y=4x-18[/tex]

[tex]\sf \implies -4x+3y=-18[/tex]

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