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## Sagot :

## Question:-

A solution has a pH of 5.4, the determination of [H+].

## Given :-

- pH:- 5.4
- pH = - log[H+]

## To find :- concentration of H+

## Answer:- Antilog(-5.4) or 4× 10-⁶

## Explanation:-

### Formula:- pH = -log H+

Take negative to other side

-pH = log H+

multiple Antilog on both side

(Antilog and log cancel each other )

Antilog (-pH) = [ H+ ]

New Formula :- Antilog (-pH) = [+H]

Now put the values of pH in new formula

Antilog (-5.4) = [+H]

we can write -5.4 as (-6+0.6) just to solve Antilog

Antilog ( -6+0.6 ) = [+H]

Antilog (-6) × Antilog (0.6) = [+H]

[tex]Antilog (-6) = {10}^{ - 6} , \\ Antilog (0.6) = 4 [/tex]

put the value in equation

[tex] {10}^{ - 6} \times 4 = [H+] \\ 4 \times {10}^{ - 6} = [H+][/tex]