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A person is dragging a packing crate of mass 100 kg across a rough horizontal floor where the coefficient of kinetic friction is 0. 400. He exerts a force f sufficient to accelerate the crate forward. At what angle above horizontal should his pulling force be directed in order to achieve the maximum acceleration?.

Sagot :

okpalawalter8

For a person dragging a packing crate of mass 100 kg, the angle above the horizontal  is mathematically given as

theta = 21.8 °

What angle above horizontal should his pulling force be directed in order to achieve the maximum acceleration?.

Generally, the equation for the Force   is mathematically given as

[tex]Fnet = F_{costheta} - F_{friction}[/tex]

Therefore

Fnet = Fcostheta - mu*((mg) - Fsintheta)

sin theta = mu*costheta

mu = tantheta

theta = tan^-1(mu)

theta = tan^-1(.400)

theta = 21.8 °

In conclusion, the angle above horizontal

theta = 21.8 °

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