masonhrd1221
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Write the equation of the line that passes through the points (-9,-9)(−9,−9) and (6,-7)(6,−7). Please help me

Sagot :

s1m1

Answer:

y = (2/15) x -(117/15)

Step-by-step explanation:

To write the equation we should know the slope m and the y-intercept b .

m= (y2-y1)/(x2-x1)

For points (x1 = -9, y1 = -9) and (x2 = 6, y2 = -7)

m = (-7 - - 9)/(6 - - 9) = (-7 + 9)/(6 +9) = 2 / 15

The general equation of a line is

y= mx + b

Our equation is

y = (2/15) x +b

To find b, substitute one of the two points, we know are on the line, in our equation. For example, we can substitute point (-9,-9)

-9 = (2/15) (-9) +b , multiply -9 by 2/15

-9 = - (18/15) +b, add -18/15 on both sides

-9 + (18/15) = b, find common denominator and add

[(-9 ·15) +18]/15 = b , simplify

-117/15 = b

So our equation is:

y = (2/15) x -(117/15)

View image s1m1
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