The pH of the solution is 10.74. the pH refers to the hydrogen ion concentration. It is a measure of the acidity of the solution.
pH is the degree of acidity or alkalinity of a solution.
The equation of the reaction is;
KOH + HBrO ==> KBrO + H2O
The number if moles of KOH =20.0 ml x 1 L / 1000 ml x 0.150 mol/L = 0.003 moles KOH
The number of moles of HBrO = 20.0 ml x 1 L / 1000 ml x 0.300 mol/L = 0.006 moles HBrO
Since the reaction is 1:2;
[BrO-] = 0.003 mols / 0.04L = 0.075M
Now the pH, is obtained from;
KBrO + H2O ==> KOH + HBrO
BrO- + H2O ==> HBrO + OH-
Kb of BrO- = 1x10-14 / 2.5x10-9 = 4x10-6
Kb = 4x10-6 = [HBrO][OH-] / [BrO-]
From the ICE table;
4x10^-6 = (x)^2 / 0.075
x = 5.48x10-4 M = [OH-]
pOH = -log 5.48x10-4 M = 3.26
pH = 14 - pOH
pH = 10.74
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