Answered

Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Explore thousands of questions and answers from a knowledgeable community of experts on our user-friendly platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

buffer is prepared by adding 275 mL of .676M of HCl to 500 mL of .525M sodium acetate. What is the pH?

Sagot :

samueladesida43

The pH of the buffer prepared by adding 275 mL of .676M of HCl to 500 mL of .525M sodium acetate is 6.45.

How to calculate pH?

The pH of a buffer solution can be calculated by initially calculating the millimoles of both the conjugate base and acid.

  • Millimoles of hydrochloric acid = 275mL × 0.676M = 185.9millimoles
  • Millimoles of sodium acetate = 500mL × 0.525M = 262.5millimoles

From, Henderson Hasselbalch equation,

pH = pKa + log conjugate base/acid

pka of HCl = -6.3

-6.3 + log 262.5/185.9

6.3 + 0.15

pH = 6.45

Therefore, the pH of the buffer prepared by adding 275 mL of .676M of HCl to 500 mL of .525M sodium acetate is 6.45.

Learn more about pH at: https://brainly.com/question/491373

Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.