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buffer is prepared by adding 275 mL of .676M of HCl to 500 mL of .525M sodium acetate. What is the pH?

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samueladesida43

The pH of the buffer prepared by adding 275 mL of .676M of HCl to 500 mL of .525M sodium acetate is 6.45.

How to calculate pH?

The pH of a buffer solution can be calculated by initially calculating the millimoles of both the conjugate base and acid.

  • Millimoles of hydrochloric acid = 275mL × 0.676M = 185.9millimoles
  • Millimoles of sodium acetate = 500mL × 0.525M = 262.5millimoles

From, Henderson Hasselbalch equation,

pH = pKa + log conjugate base/acid

pka of HCl = -6.3

-6.3 + log 262.5/185.9

6.3 + 0.15

pH = 6.45

Therefore, the pH of the buffer prepared by adding 275 mL of .676M of HCl to 500 mL of .525M sodium acetate is 6.45.

Learn more about pH at: https://brainly.com/question/491373

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