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buffer is prepared by adding 275 mL of .676M of HCl to 500 mL of .525M sodium acetate. What is the pH?

Sagot :

The pH of the buffer prepared by adding 275 mL of .676M of HCl to 500 mL of .525M sodium acetate is 6.45.

How to calculate pH?

The pH of a buffer solution can be calculated by initially calculating the millimoles of both the conjugate base and acid.

  • Millimoles of hydrochloric acid = 275mL × 0.676M = 185.9millimoles
  • Millimoles of sodium acetate = 500mL × 0.525M = 262.5millimoles

From, Henderson Hasselbalch equation,

pH = pKa + log conjugate base/acid

pka of HCl = -6.3

-6.3 + log 262.5/185.9

6.3 + 0.15

pH = 6.45

Therefore, the pH of the buffer prepared by adding 275 mL of .676M of HCl to 500 mL of .525M sodium acetate is 6.45.

Learn more about pH at: https://brainly.com/question/491373