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Sagot :
Answer:
See below for answers and explanations
Step-by-step explanation:
Part A
The average rate of change of a function over the interval [tex][a,b][/tex] is equal to [tex]\frac{f(b)-f(a)}{b-a}[/tex], hence:
[tex]\frac{f(b)-f(a)}{b-a}\\\\\frac{f(9)-f(5)}{9-5}\\\\\frac{14-(-4)}{9-5}\\ \\\frac{14+4}{4}\\ \\\frac{18}{4}\\ \\\frac{9}{2}[/tex]
Therefore, the average rate of change of [tex]f(x)[/tex] over the interval [tex][5,9][/tex] is [tex]\frac{9}{2}[/tex].
Part B
Do the same thing as in Part A:
[tex]\frac{f(b)-f(a)}{b-a}\\ \\\frac{f(1)-f(0.25)}{1-0.25}\\ \\\frac{2-5}{0.75}\\ \\\frac{-3}{0.75}\\ \\-4[/tex]
Therefore, the average rate of change of [tex]g(x)[/tex] over the interval [tex][0.25,1][/tex] is [tex]-4[/tex].
Part C
To interpret our answer from Part B in terms of the real world it represents, we say that between 0.25 seconds and 1 second, the ball falls at a rate of 4 feet per second (since our average rate of change is negative).
The average rates of change are:
- a) 4.5
- b) -4
- c) It means that in the interval, for each second that passes the height decreases by 4ft.
How to get the average rate of change?
For a function f(x), the average rate of change on the interval [a, b] is:
[tex]r = \frac{f(b) - f(a)}{b -a}[/tex]
a) Here we have:
[tex]r = \frac{F(9) - F(5)}{9 - 5} = \frac{14 - (-4)}{4} = 4.5[/tex]
b) Now we look at g(x) on the interval [0.25, 1]
Notice that g(0.25) = 5 and g(1) = 2
Then we have:
[tex]r = \frac{2 - 5}{1 - 0.25} = -4[/tex]
c) That average rate of change means that, in average, in that interval in each second the height decreases by 4 ft.
If you want to learn more about average rates of change:
https://brainly.com/question/8728504
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