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At 4.5 atm of pressure, the solubility of a gas is 9.5 g/L.
How much gas, in grams, will dissolve in 1 L if the pres.
sure is reduced by 3.5 atm?


Sagot :

For a gas at 4.5 atm of pressure, the solubility of a gas is 9.5 g/L.

How much gas, in grams, is mathematically given as

s2=8.3782grams

What is the amount of gas in grams?

Generally, the equation for the   is mathematically given as

Si /S2 √P1/√P2

Therefore

[tex]s2=9.5*\sqrt{3.5}/\sqrt{4.5}[/tex]

s2=8.3782g

In conclusion. The solubility is

s2=8.3782g

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