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The vertices of a quadrilateral drawn in a coordinate plane are (-6,6), (4,6), (2,-5), and (-6,-9). what is the length of the side joining the vertex in quadrant i to the vertex in quadrant 11? a) 2 b) 8 c) 10 d) 12​

Sagot :

Using the formula for the distance between two points, it is found that the length of the side joining the vertex in quadrant i to the vertex in quadrant ii is given by:

c) 10

What is the distance between two points?

Suppose that we have two points, [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex]. The distance between them is given by:

[tex]D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

In quadrant I, both coordinates are positive, hence the vertex is (4,6). In quadrant II, x is negative while y is positive, hence the vertex is (-6,6). Thus, the distance is given by:

[tex]D = \sqrt{(-6 - 4)^2+(6 - 6)^2} = 10[/tex]

Which means that option C is correct.

More can be learned about the distance between two points at https://brainly.com/question/18345417