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A metal bar is in the xy-plane with one end of the bar at the origin. a force f⃗ =( 6.88 n )i^+( -2.62 n )j^ is applied to the bar at the point x= 2.88 m , y= 3.70 m .

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The work done by the applied force on the metal bar in the xy-plane is 34.52 J.

Work done by the applied force

The work done by the applied force is determined from the product of the force and the displacement of the object.

Magnitude of the force

The magnitude of the force is calculated as follows;

|F| = √(Fy² + Fx²)

|F| = √(6.88² + 2.62²)

|F| = 7.36 N

Resultant displacement of the object

The resultant displacement of the object is calculated as follows;

|s| = √(y² + x²)

|s| = √(3.7² + 2.88²)

|s| = 4.69 m

Work done

W = F.s

W = 7.36 x 4.69

W = 34.52 J

The complete question is below:

Find the work done by the applied force.

Learn more about work done here: https://brainly.com/question/8119756

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