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A coffee filter of mass 1.3 grams dropped from a height of 3 m reaches the ground with a speed of 0.5 m/s. How much kinetic energy Kair did the air molecules gain from the falling coffee filter

Sagot :

Answer: .0380575J

Explanation:

The coffee filter originally only had potential energy, which can be found by:

PE = m * g * h → PE = .0013 * 9.8 * 3 = .03822 J

*Note the mass must be in kg!!!

All of this energy should be converted to kinetic energy, but the air molecules take some of the energy; the energy they gain can be found by finding how much energy the filter has at the bottom of its fall, and subtracting this from the original energy to see how much was lost;

All of the energy at the bottom equals kinetic energy, which can be found by:

KE = 1/2 * m * v^2 → KE = 1/2 * .0013 * .5^2 = .0001625 J

Thus, the air gained .03822 - .0001625 = .0380575J :)

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