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Sagot :
The number of atoms of nitrogen present in 137 grams of N₂O₃ in 2.1 × 10²⁴.
What is Avogadro's number?
Avogadro's number is that number which tells about the number of atoms or entities of any substance present in one mole of any substance, i.e. 1 mole = 6.022 × 10²³
First we have to convert mass of N₂O₃ to moles by using the below formula:
n = W/M, where
W = given mass = 137g
M = molar mass = 76g/mol
Moles of N₂O₃ = 137 / 76 = 1.8mol
From the stoichiometry of the mass and formula it is clear that:
In 76g of N₂O₃ = 2 moles of Nitrogens are present
In 137g of N₂O₃ = 2/76×137=3.6 moles of Nitrogens are present
No. of N atoms in 3.6 moles = 3.6 × 6.022 × 10²³ = 2.1 × 10²⁴
Hence option (D) is correct.
To know more about Avogadro's number, visit the below link:
https://brainly.com/question/10614569
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