Answered

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HELLLPP ME PLEASSEEE!!!!!

Consider the two circles shown.


To show that circle P is similar to circle Q, circle P is translated t units to the right. The image is then dilated about its center by a scale factor of s.
What are the values of t and s?
Show me:
(t) What is the horizontal distance between the center of circle P to the center of circle Q?
(s) What is the scale factor dilating from circle P to circle Q?

HELLLPP ME PLEASSEEE Consider The Two Circles Shown To Show That Circle P Is Similar To Circle Q Circle P Is Translated T Units To The Right The Image Is Then D class=

Sagot :

MrRoyal

The similar circles P and Q can be made equal by dilation and translation

  • The horizontal distance between the center of circles P and Q is 11.70 units
  • The scale factor of dilation from circle P to Q is 2.5

The horizontal distance between their centers?

From the figure, we have the centers to be:

P = (-5,4)

Q = (6,8)

The distance is then calculated using:

d = √(x2 - x1)^2 + (y2 - y1)^2

So, we have:

d = √(6 + 5)^2 + (8 - 4)^2

Evaluate the sum

d = √137

Evaluate the root

d = 11.70

Hence, the horizontal distance between the center of circles P and Q is 11.70 units

The scale factor of dilation from circle P to Q

We have their radius to be:

P = 2

Q = 5

Divide the radius of Q by P to determine the scale factor (k)

k = Q/P

k = 5/2

k = 2.5

Hence, the scale factor of dilation from circle P to Q is 2.5

Read more about dilation at:

https://brainly.com/question/3457976

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