Welcome to Westonci.ca, where finding answers to your questions is made simple by our community of experts. Get quick and reliable solutions to your questions from knowledgeable professionals on our comprehensive Q&A platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
The graph of the normal distribution of the random sample size of 24 will have the shape of a bell curve.
The value of k such that P(-2.069 < T < k) = 0.965 is 2.5
How to determine the value of k?
The sample size is given as:
n = 24
This means that the degrees of freedom is:
df = n - 1
df = 24 - 1
df = 23
The probability is given as:
P(-2.069 < T < k) = 0.965
This can be rewritten as:
P(T>-2.069) - P(T>k) = 0.965
The value of P(T>-2.069) at a degrees of freedom of 23 and [tex]\alpha[/tex] = 0.025 is 0.975
So, we have:
0.975 - P(T>k) = 0.965
Collect like terms
P(T>k) = 0.975 - 0.965
Evaluate the difference
P(T>k) = 0.01
The value of k that makes P(T>k) = 0.01 is 2.5.
So, we have:
k = 2.5
Hence, the value of k is 2.5
Read more about normal distribution at:
https://brainly.com/question/4079902
We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.