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Kyle has a storage box that is 2 ft. Long, 3 ft. High, and has a volume of 12 ft. 3. Myla has a storage box that is 4 ft. High, 2 ft. Long, and has a volume of 16 ft. 3. What are the widths of Kyle and Myla's boxes? Explain how you know.

Sagot :

The widths of Kyle's and Myla's boxes for the considered case are obtained as: width of Kyle's box = 2 ft, width of Myle's box = 2 ft

How to find the volume of a right rectangular prism?

Suppose that the right rectangular prism in consideration be having its dimensions as 'a' units, 'b' units, and 'c' units, then its volume is given as:

[tex]V = a\times b \times c \: \: unit^3[/tex]

A storage box oftenly has the shape of a right rectangular prism.

We're specified that:

For Kyle's box:

  • Volume of the box = 12 cubic ft
  • Length of the box = 2 ft
  • Height of the box = 3 ft
  • Width of the box = x ft (suppose)

For Myla's box:

  • Volume of the box = 16 cubic ft
  • Length of the box = 4 ft
  • Height of the box = 2 ft
  • Width of the box = y ft (suppose)

Using the formula for volume of right rectangular prism to find the missing widths:

  • Case 1: For Kyle's box:

[tex]12 = 2 \times 3 \times x\\12 = 6 \times x\\\text{Dividing both the sides by 6}\\2= x\\x = 2 \: \rm ft[/tex]

  • Case 2: For Myla's box:

[tex]16 = 4 \times 2 \times y\\16 = 8 \times x\\\text{Dividing both the sides by 8}\\2= y\\y = 2 \: \rm ft[/tex]

Thus, the widths of Kyle's and Myla's boxes for the considered case are obtained as: width of Kyle's box = 2 ft, width of Myle's box = 2 ft

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