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If a 40 N block is resting on a rough horizontal table with a
coefficient of static friction p=0.60, then what is the force of
static friction acting on the block?



Sagot :

Based in the relationship between static frictional force and coefficient of static friction, the force of static friction is 24 N.

What is friction?

Friction is a force that opposes the relative motion of an object moving over another at their surafce of contact.

Frictional force is constant for each type of material. This constant is known as coefficient of friction.

The coefficient of friction is given as follows:

  • Coefficient of friction = Frictional force/normal reaction

From the data given:

  • coefficient of static friction p = 0.60
  • Weight of block = 40 N

Force of static friction = 0.60 × 40

Force of static friction = 24 N.

Therefore, the force of static friction is 24 N.

Learn more about static friction at: https://brainly.com/question/11361910

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