Answered

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Solve the following equation for x.

12x^2-36x=0

Sagot :

DᴀʀᴋPᴀʀᴀᴅᴏx

[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]

Let's solve for x ~

[tex]\qquad \sf  \dashrightarrow \:12 {x}^{2} - 36x = 0[/tex]

[tex]\qquad \sf  \dashrightarrow \:12 x({x}^{} - 3) = 0[/tex]

[tex]\qquad \sf  \dashrightarrow \:12x = 0 \: \: or \: \: x - 3 = 0[/tex]

[tex]\qquad \sf  \dashrightarrow \:x = 0 \: \: or \: \: x = 3[/tex]

Therefore, the possible values of x are 0 and 3

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