Westonci.ca is your go-to source for answers, with a community ready to provide accurate and timely information. Join our platform to connect with experts ready to provide precise answers to your questions in various areas. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
Given :-
- Constant force, F = 20 N
- Mass of Car = 32 kg
- Initial speed, u = 4 m/s
- Final Speed = 9 m/s
To Find:-
- Duration for which force is appiled
Solution:-
[tex]\green{ \underline { \boxed{ \sf{Force,F= Mass \times Acceleration }}}}[/tex]
So,
[tex] \sf Acceleration,a = \frac{Force}{Mass}[/tex]
[tex] \sf \implies \frac{20}{32} [/tex]
[tex]\implies \frac{5}{8} m/s^2[/tex]
Now,
By first equation of motion -
[tex]\green{ \underline { \boxed{ \sf{v-u=at}}}}[/tex]
So,
[tex]\sf t = \dfrac{v-u}{a} [/tex]
where
- v = final velocity
- u = initial velocity
- a = acceleration
- t = time duration
Putting Values -
[tex]\sf t = \dfrac{9-4}{ \dfrac{5}{8}} [/tex]
[tex]\sf t = \dfrac{5}{ \dfrac{5}{8}} [/tex]
[tex]\sf t = \cancel5 \times \dfrac{8}{\cancel{5}} [/tex]
[tex]\sf t = 8 \:seconds[/tex]
>>>Therefore, Force is applied for 8 seconds.
Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.
