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A constant net force of 20 n is applied to a 32 kg car, causing it to speed up from 4. 0 to 9. 0 m/s. how long is the force applied?

Sagot :

Given :-

  • Constant force, F = 20 N
  • Mass of Car = 32 kg
  • Initial speed, u = 4 m/s
  • Final Speed = 9 m/s

To Find:-

  • Duration for which force is appiled

Solution:-

[tex]\green{ \underline { \boxed{ \sf{Force,F= Mass \times Acceleration }}}}[/tex]

So,

[tex] \sf Acceleration,a = \frac{Force}{Mass}[/tex]

[tex] \sf \implies \frac{20}{32} [/tex]

[tex]\implies \frac{5}{8} m/s^2[/tex]

Now,

By first equation of motion -

[tex]\green{ \underline { \boxed{ \sf{v-u=at}}}}[/tex]

So,

[tex]\sf t = \dfrac{v-u}{a} [/tex]

where

  • v = final velocity
  • u = initial velocity
  • a = acceleration
  • t = time duration

Putting Values -

[tex]\sf t = \dfrac{9-4}{ \dfrac{5}{8}} [/tex]

[tex]\sf t = \dfrac{5}{ \dfrac{5}{8}} [/tex]

[tex]\sf t = \cancel5 \times \dfrac{8}{\cancel{5}} [/tex]

[tex]\sf t = 8 \:seconds[/tex]

>>>Therefore, Force is applied for 8 seconds.

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