Westonci.ca is the premier destination for reliable answers to your questions, brought to you by a community of experts. Discover in-depth answers to your questions from a wide network of experts on our user-friendly Q&A platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
Given :-
- Constant force, F = 20 N
- Mass of Car = 32 kg
- Initial speed, u = 4 m/s
- Final Speed = 9 m/s
To Find:-
- Duration for which force is appiled
Solution:-
[tex]\green{ \underline { \boxed{ \sf{Force,F= Mass \times Acceleration }}}}[/tex]
So,
[tex] \sf Acceleration,a = \frac{Force}{Mass}[/tex]
[tex] \sf \implies \frac{20}{32} [/tex]
[tex]\implies \frac{5}{8} m/s^2[/tex]
Now,
By first equation of motion -
[tex]\green{ \underline { \boxed{ \sf{v-u=at}}}}[/tex]
So,
[tex]\sf t = \dfrac{v-u}{a} [/tex]
where
- v = final velocity
- u = initial velocity
- a = acceleration
- t = time duration
Putting Values -
[tex]\sf t = \dfrac{9-4}{ \dfrac{5}{8}} [/tex]
[tex]\sf t = \dfrac{5}{ \dfrac{5}{8}} [/tex]
[tex]\sf t = \cancel5 \times \dfrac{8}{\cancel{5}} [/tex]
[tex]\sf t = 8 \:seconds[/tex]
>>>Therefore, Force is applied for 8 seconds.
Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.
