Welcome to Westonci.ca, the place where your questions are answered by a community of knowledgeable contributors. Our Q&A platform provides quick and trustworthy answers to your questions from experienced professionals in different areas of expertise. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
Given -
- If l || m, m∠1 = (13x + 24)°, and m∠2 = (5x-6)°,
To find -
- m∠2.
Concept -
Whenever two parallel lines are cut by a transversal, an interesting relationship exists between the two interior angles on the same side of the transversal. These two interior angles are supplementary angles. Hence, according to the figure l and m are two parallel lines and t is the transversal intersecting them then ∠1 + ∠2 = 180°.
Solution -
[tex]\rightarrow\sf{(13x+24)^{ \circ}+(5x-6)^{ \circ}=180^{ \circ}}[/tex]
[tex]\rightarrow\sf{13x+5x+24-6=180}[/tex]
[tex]\rightarrow\sf{18x+18=180}[/tex]
[tex]\rightarrow\sf{18x+18=180}[/tex]
[tex]\rightarrow\sf{18(x+1)=180}[/tex]
[tex]\rightarrow\sf{x+1=\frac{180}{18}}[/tex]
[tex]\rightarrow\sf{x+1=10}[/tex]
[tex]\rightarrow\sf{x=10-1}[/tex]
[tex]\rightarrow\boxed{\bf{x=9}}[/tex]
m∠2 = (5x-6)° = {5(9) - 6}° = {45 - 6}°= 39°
Henceforth, m∠2 = 39°
We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.