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What is the volume of a sphere with a radius of 3 m, rounded to the nearest tenth

Sagot :

Given:-

[tex]\rightarrow[/tex]Radius(r) of sphere = 3m

To Find:-

[tex]\rightarrow[/tex] Volume of the sphere.

Formula Used:-

[tex]\rightarrow[/tex]Volume of sphere = [tex]\sf{\frac{4}{3}πr^3}[/tex]

Solution:-

[tex]\rightarrow[/tex]Volume of sphere = [tex]\sf{\frac{4}{3}πr^3}[/tex](putting the value of r(radius) from the above given and pie(π) = [tex]\sf{\frac{22}{7}}[/tex])

[tex]\rightarrow[/tex][tex]\sf{=\frac{4}{3}×\frac{22}{7}×3^3}[/tex]

[tex]\rightarrow[/tex][tex]\sf{=\frac{4}{3}×\frac{22}{7}×27}[/tex]

[tex]\rightarrow[/tex][tex]\sf{=\frac{2,376}{21}}[/tex]

[tex]\rightarrow[/tex][tex]\sf{=113.14m^3}[/tex]

Therefore, the volume of the sphere [tex]\sf{=113.14m^3}[/tex], which can be rounded off to it's nearest tenth as [tex]\sf{113.1m^3}[/tex]

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