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Sagot :
Square Root of 9:-
[tex]\rightarrow[/tex]Square root of 9 is a whole number that is multiplied by itself to get the original number. The actual value of square root of 9 is 3.
√9 = ±3
[tex]\rightarrow[/tex]If we square +3 or -3, the resulting value will be equal to 9.
[tex]\sf{(+3)^2 = 9}[/tex]
[tex]\sf{(-3)^2 = 9}[/tex]
How to find?:-
[tex]\rightarrow[/tex]Number 9 is an odd number and not a prime number. Prime numbers have only two factors, 1 and the number itself. But as we know, 9 have three multiple factors, 1, 3 and 9 itself. Thus, we can write the number 9 in the form of multiple as;
- [tex]\sf{1 × 9 = 9}[/tex]
- [tex]\sf{3 × 3 = 9}[/tex]
- [tex]\sf{9 × 1 = 9}[/tex]
[tex]\rightarrow[/tex]You know that number 9 is a multiple of 3 or when 3 is multiplied by itself, we get the number 9. Therefore, we can write the square root of 9 as;
➾[tex]\sf{\sqrt{9}}[/tex]
➾[tex]\sf{\sqrt{3×3}}[/tex]
➾[tex]\sf{\sqrt{3^2}}[/tex]
[tex]\rightarrow[/tex]The square cancels the square root of a number. Therefore, if we cancel the square root with a square in the above expression, we get,
➾[tex]\sf{\sqrt{9}}[/tex] = ±3
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