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 find the equation of the line that is parallel to the line Y equals 3X -6 and passes through the points (1 -8). Write the equation in point slope form

Sagot :

hello!

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Parallel lines have the same slope.

So if the given line has a slope of 3, then the line parallel to it has the same slope (3)

Now, let's write the equation of the line in Point-Slope Form.

Remember, point-slope form looks like so:-

[tex]\bigstar{\underline{\boxed{\pmb{y-y1=m(x-x1)}}}[/tex]

Where

y₁ is the y-coordinate of the point that the line passes through

m is the slope

x₁ is the x-coordinate of the point that the line passes through

In this case,

y₁ is equal to -8

m is equal to 3

x₁ is equal to 1

Plug in the values:

[tex]\longrightarrow\sf{y-(-8)=3(x-1)}[/tex]

Simplify:

[tex]\longrightarrow\sf{y+8=3(x-1)}[/tex]

and we're done!

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note:-

Hope everything is clear; if you need any more explanation/clarification, kindly let me know, and I will comment and/or edit my answer :)