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Sagot :
hello!
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Perpendicular lines have slopes that are opposite reciprocals.
This means we take a number, flop it over, and change its sign.
In this case, we take [tex]\boxed{-3}[/tex], change its sign:
[tex]\boxed{3}[/tex]
3 can also be written as
[tex]\boxed{\frac{3}{1} }[/tex]
Now the numerator & denominator switch places:
[tex]\boxed{\frac{1}{3}}[/tex]
So that's the slope of the new line.
Now, let's write the equation in point-slope form:-
[tex]\bigstar{\underline{\boxed{\pmb{y-y_1=m(x-1)}}}[/tex]
Where
y₁ is the y-coordinate of the point (in this case, y₁ = 3)
m = slope (1/3)
x₁= the x-coordinate of the point (in this case, it's -2)
Plug in the values:-
[tex]\bigstar{\boxed{\pmb{y-3=\frac{1}{3}(x-(-2)}}[/tex]
[tex]\bigstar{\boxed{\pmb{y-3=\frac{1}{3}(x+2)} }\longleftarrow\sf{Point-Slope~Formula:)}}[/tex]
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note:-
Hope everything is clear; if you need any clarification/explanation, kindly let me know, and I will comment and/or edit my answer :)
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