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Find the height of the building to the nearest foot in the diagram below. Show work.

Find The Height Of The Building To The Nearest Foot In The Diagram Below Show Work class=

Sagot :

fieryanswererft

Answer:

height : 150 feet

Step-by-step explanation:

[tex]\sf \sf tan(x)= \dfrac{opposite}{adjacent}[/tex]

using tan rule:

[tex]\hookrightarrow \sf tan(62)= \dfrac{b}{80}[/tex]

[tex]\hookrightarrow \sf b = tan(62)*80[/tex]

[tex]\hookrightarrow \sf b =150.46 \ feet[/tex]

Nayefx

Answer:

[tex]\approx 150 \: ft[/tex]

Step-by-step explanation:

recall sohcahtoa

  • sin(x)=opposite/hypotenuse
  • cos(x)=adjacent/hypotenuse
  • tan(x)=opposite/adjacent

here,

  • The adjacent side is 80 ft
  • x°=62°
  • The opposite side is the height

To find:

  • The opposite side or the height

since we are given the value of adjacent side and need to figure out the opposite side , we will work with tan function,

So,

[tex] \tan( {62}^{ \circ} ) = \dfrac{h}{80} [/tex]

[tex] \implies \: h = 80\tan( {62}^{ \circ} ) [/tex]

using calculator,we acquire

[tex] \implies \: h \approx 150 \: ft[/tex]

hence, the height of the building is approximately 150ft

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