Based on the mean of the subscribers, the sample size, and the standard deviation, the probability of females being at most 0.25 is 0.2202.
The probability that they are between 0.22 and 0.28 is 0.2703.
The probability that they are within 0.03 of the population proportion is 0.3566.
What is the probability that they are at most 0.25?
Using Excel, we shall assume that the distribution is normally distributed.
We can therefore use the NORM.DIST function:
=NORM.DIST(0.25,0.3,0.0648,TRUE)
= 0.2202
What is the probability that they are between 0.22 and 0.28?
=NORM.DIST(0.28,0.3,0.0648,TRUE) - NORM.DIST(0.22,0.3,0.0648,TRUE)
= 0.2703
What is the probability that they are within 0.03 of the population proportion?
X high = 0.30 + 0.03
= 0.33
X low = 0.30 - 0.03
= 0.27
= NORM.DIST(0.33,0.3,0.0648,TRUE) - NORM.DIST(0.27,0.3,0.0648,TRUE)
= 0.3566.
Find out more on probability at https://brainly.com/question/1846009.
