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Answer the questions in the image.

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Sagot :

#1

  • Radius=9/2=4.5in

Area:-

  • πr²
  • 4.5^2π
  • 20.25πin^2
  • 63.58in^2

#2

  • Side=a=4in

Area:-

  • a²
  • 4²
  • 16in^2

#3

Area of the white part=Area of circle-Area of square

  • 63.585-16
  • 47.585in^2

#4

Probability

  • 16/63.585
  • 0.252

#5

Probability

  • 47.58/63.585
  • 0.75
aestheticsylveon1

Answer:

1. 63.62 in².

2. 16 in².

3. 47.62 in².

4. 0.25 .

5. 0.74 .

Step-by-step explanation:

1.

Solution,

Given,

Diameter = 9 inch.

Now,

Area = πr²

Diameter = r²

Then,

Area = 1/4 πd²

= 1/4 π9²

= 63.62 in².

2.

Solution,

Given,

Length of a Side = 4 inch.

Now,

Area = L²

= 4²

= 16 in².

3.

Solution,

Given,

Area of the Circle = 63.62 in².

Area of the Square = 16 in².

Now,

Area of The White Part of the Circle = Area of Circle - Area of Square

= 63.62 in² - 16 in².

= 47.62 in².

4.

Solution,

Given,

Area of the Square = 16 in².

Area of the Circle = 63.62 in².

Now,

The probability of landing in the Square = Square Area / Circle Area

= 16 / 63.62

= 0.25 .

5.

Solution,

Given,

White Part of the Circle = 47.62 in².

Area of the Circle = 63.62 in².

Now,

The probability of landing in the white Part = White Area / Circle Area.

= 47.62 / 63.62

= 0.74 .

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