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If the point (x,square root 3/2) is on the unit circle, what. is x?

Sagot :

Answer:

[tex]x=\pm\frac{1}{2}[/tex]

Step-by-step explanation:

On a unit circle, [tex](x,y)=(\cos\theta,\sin\theta)[/tex], so [tex]\sin\theta=\frac{\sqrt{3}}{2}[/tex] in this case. If you look at the attached circle, the only time that the y-coordinate is [tex]\frac{\sqrt{3}}{2}[/tex] is when [tex]x=-\frac{1}{2}[/tex] and [tex]x=\frac{1}{2}[/tex], which correspond to angles of [tex]\theta=\frac{2\pi}{3}[/tex] and [tex]\theta=\frac{\pi}{3}[/tex] respectively

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