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What is the temperature of 12.20 mol of gas in a 18.35 l tank at 16.40 atm? round your answer to the tenths place.

Sagot :

Lanuel

Based on the calculations, the temperature of this ideal gas is equal to 300.5 K.

How to calculate the temperature.

Mathematically, the temperature of an ideal gas is given by this formula:

[tex]PV=nRT\\\\T=\frac{PV}{nR}[/tex]

Where:

  • P is the pressure.
  • R is the ideal gas constant.
  • T is the temperature.
  • n is the number of moles.
  • V is the volume.

Given the following data:

Number of moles = 12.20 moles.

Volume = 18.35 L.

Pressure = 16.40 atm.

Substituting the given parameters into the formula, we have;

[tex]T=\frac{16.40 \times 18.35}{12.20 \times 0.0821}\\\\T=\frac{300.94}{1.00162}[/tex]

T = 300.5 K.

Read more on temperature here: brainly.com/question/3173452

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