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Sagot :
The time that is required to retrieve the object (including TCP connection establishment) when [tex]4S/R > S/R > RTT > 2S/R[/tex] is equal to [tex]\frac{14S}{R}+4RTT[/tex]
How to calculate the time needed to receive all objects.
In this scenario, we would denote the round-trip time that exist between the web server and the client with [tex]RTT[/tex] and assume that it is constant.
The time that is required to retrieve the object when [tex]4S/R > S/R > RTT > 2S/R[/tex] would be calculated by adding the round trip of sender and reciever together as follows:
Round trip = RTT + RTT
Next, we would determine the delay in packet transmission:
Note: [tex]\frac{8S}{R}+\frac{4S}{R}=\frac{12S}{R}[/tex]
[tex]Time = (\frac{S}{R} +RTT)+(\frac{S}{R} +RTT)+(\frac{12S}{R}) +RTT+RTT\\\\Time = \frac{14S}{R}+4RTT[/tex]
When [tex]S/R +RTT > 4S/R[/tex], we have:
The time that is required to retrieve the object would be calculated by adding the round trip of sender and reciever together as follows:
[tex]Time = (\frac{S}{R} +RTT)+(\frac{S}{R} +RTT)+(\frac{8S}{R}) +RTT+RTT\\\\Time = \frac{11S}{R}+5RTT[/tex]
The time that is required to retrieve the object when [tex]S/R > RTT[/tex] would be calculated by adding the round trip of sender and reciever together as follows:
[tex]Time = (\frac{S}{R} +RTT)+(\frac{14S}{R}) +RTT\\\\Time = \frac{15S}{R}+3RTT[/tex]
Read more on round trip here: https://brainly.com/question/6884622
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