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Sagot :

MidnightShowers

Answer:

given - circumference of the coin = 122 inches.

  • to calculate - radius of the coin.

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[tex]\fbox\pink{Solution -}[/tex]

[tex]circumference = 2\pi \: r \\ \\ r = \frac{circumference}{2\pi} \\ \\r = \frac{\cancel{122}}{\cancel2 \times \frac{22}{7} } \\ \\ r = \frac{61}{ \frac{22}{7} } \\ \\ r = 61 \times \frac{7}{22} \\ \\ r = \frac{427}{22} \\ \\ r = 19.41 \: inches \: (approx.)[/tex]

hope helpful :D

Answer :

  • 19.42 inches

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Step-by-step explanation :

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We know that,

[tex]{\longrightarrow \qquad \frak {\pmb{ 2 \pi r = Circumference_{(circle)} }}}[/tex]

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Here,

  • r is the radius of the circle.

  • We'll take the value of π as 3.14 . (Answer may be different if we take the value of it as 22/7)

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Now, substituting the values :

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[tex]{\longrightarrow \qquad \sf{ 2 \times 3.14 \times r = 122}}[/tex]

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[tex]{\longrightarrow \qquad \sf{ 6.28 \times r = 122}}[/tex]

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[tex]{\longrightarrow \qquad \sf{ r = \dfrac{122}{6.28} }}[/tex]

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[tex]{\longrightarrow \qquad \frak{\pmb{ r = 19.42}}}[/tex]

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Therefore,

  • The radius of the object is 19.40 inches approximately (Rounded to nearest tenth)

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