The area of the considered triangle RST is given by: Option A: 9 sq. units.
If we have:
Then we get:
Area of a triangle = [tex]\dfrac{b \times h}{2} \: \rm unit^2[/tex]
The missing image is attached below.
If we take the base of the triangle as RS, then as the line UT is perpendicular to RS (as RS is parallel to x axis and UT is parallel to y axis) and touching from the base line RS to T, thus, it can be taken as height.
Thus, we have:
Area of RST = half of length of RS (base) times length of UT (height)
As visible from image, we have:
Length of RS = 6 blocks of unit length = 6 units
Similarly, length of UT = 3 units
Thus, we get:
Area of RST = [tex]\dfrac{6 \times 3}{2} = 9 \: \rm unit^2[/tex]
Thus, the area of the considered triangle RST is given by: Option A: 9 sq. units.
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