Nobody1278
Answered

Looking for answers? Westonci.ca is your go-to Q&A platform, offering quick, trustworthy responses from a community of experts. Experience the ease of finding reliable answers to your questions from a vast community of knowledgeable experts. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

What is an equation of the line perpendicular to y=-x-2 and through (-2, 4)?

I would really appreciate the help, I've been stuck on this problem for awhile.​

Sagot :

Snor1ax

Answer: y = x + 6

Step-by-step explanation:

[tex]\mathrm{Find\:the\:line\:}\mathbf{y=mx+b}\mathrm{\:perpendicular\:to\:}y=-x-2\mathrm{\:that\:passes\:through\:}\left(-2,\:4\right)[/tex]

[tex]\mathrm{For\:a\:line\:equation\:for\:the\:form\:of\:}\mathbf{y=mx+b}\mathrm{,\:the\:slope\:is\:}\mathbf{m}[/tex]

[tex]m=-1[/tex]

[tex]\mathrm{The\:perpendicular\:slope\:is\:the\:negative\:reciprocal\:of\:the\:given\:slope}[/tex]

[tex]\left(-1\right)m_p=-1[/tex]

[tex]\frac{\left(-1\right)m_p}{-1}=\frac{-1}{-1}[/tex]

[tex]m_p=1[/tex]

[tex]\mathrm{Compute\:the\:line\:equation\:}\mathbf{y=mx+b}\mathrm{\:for\:slope\:m=}1\mathrm{\:and\:passing\:through\:}\left(-2,\:4\right)[/tex][tex]\mathrm{Plug\:the\:slope\:}1\mathrm{\:into\:}y=mx+b[/tex]

[tex]y=x+b[/tex]

[tex]\mathrm{Plug\:in\:}\left(-2,\:4\right)\mathrm{:\:}\quad \:x=-2,\:y=4[/tex]

[tex]4=\left(-2\right)+b[/tex]

[tex]-2+b=4[/tex]

[tex]\mathrm{Add\:}2\mathrm{\:to\:both\:sides}[/tex]

[tex]-2+b+2=4+2[/tex]

[tex]\text{Simplify}[/tex]

[tex]b=6[/tex]

[tex]\mathrm{Construct\:the\:line\:equation\:}\mathbf{y=mx+b}\mathrm{\:where\:}\mathbf{m}=1\mathrm{\:and\:}\mathbf{b}=6[/tex]

[tex]y=x+6[/tex]

Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.