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What is the equation for the circle with center (-9, 5) and radius 4

Sagot :

semsee45

Answer:

[tex]\sf (x+9)^2+(y-5)^2=16[/tex]

Step-by-step explanation:

Standard equation of a circle:  [tex]\sf (x-h)^2+(y-k)^2=r^2[/tex]

(where (h, k) is the center of the circle and r is the radius)

Given:

  • center = (-9, 5)
  • radius = 4

Substituting given values into the equation:

[tex]\sf \implies (x-(-9))^2+(y-5)^2=4^2[/tex]

[tex]\sf \implies (x+9)^2+(y-5)^2=16[/tex]
  • (h,k)=(-9,5)
  • r=4

Equation:-

  • (x-h)²+(y-k)²=r^2
  • (x-(-9))2+(y-5)^2=4^2
  • (x+9)^2+(y-5)^2=16
  • x^2+18x+81+y^2-10x+25=16[/tex]
  • [tex]\\ \rm\rightarrowtail x^2+y^2+8x+90=0[/tex]
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