Answered

Discover a wealth of knowledge at Westonci.ca, where experts provide answers to your most pressing questions. Explore thousands of questions and answers from a knowledgeable community of experts ready to help you find solutions. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

What is the equation for the circle with center (-9, 5) and radius 4

Sagot :

semsee45

Answer:

[tex]\sf (x+9)^2+(y-5)^2=16[/tex]

Step-by-step explanation:

Standard equation of a circle:  [tex]\sf (x-h)^2+(y-k)^2=r^2[/tex]

(where (h, k) is the center of the circle and r is the radius)

Given:

  • center = (-9, 5)
  • radius = 4

Substituting given values into the equation:

[tex]\sf \implies (x-(-9))^2+(y-5)^2=4^2[/tex]

[tex]\sf \implies (x+9)^2+(y-5)^2=16[/tex]
  • (h,k)=(-9,5)
  • r=4

Equation:-

  • (x-h)²+(y-k)²=r^2
  • (x-(-9))2+(y-5)^2=4^2
  • (x+9)^2+(y-5)^2=16
  • x^2+18x+81+y^2-10x+25=16[/tex]
  • [tex]\\ \rm\rightarrowtail x^2+y^2+8x+90=0[/tex]
We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.